B.E./B.TECH.DEGREE FOURTH
UNIT EXAMINATIONS, SEPTEMBER - 2012
REGULATIONS 2008
SECOND YEAR / THIRD
SEMESTER
AE
2202 AERO ENGINEERING THERMODYNAMICS
AERONAUTICAL
ENGINEERING
Time: 90 Minutes Date:
22.09.2012 Maximum:50 marks
ANSWER ALL QUESTIONS
PART
– A (7 x 2 =14
marks)
1. What are the assumptions made for air
standard cycle analysis?
2. Define Mean effective pressure.
3. Compare otto, diesel and dual cycles
4. Mention the various processes of
carnot cycle, otto cycle, Diesel cycle, Dual cycle and Brayton cycle.
5.
Define compression ratio and expansion ratio
6. Define pressure ratio and cut off
ratio.
7. Differentiate
petrol and Diesel engines.
PART
– B (3 x 12 =36 marks)
8.
Derive
the expression for air standard efficiency and mean effective pressure of an constant
volume cycle.
or
9.
An engine working on the Otto cycle
is supplied with air at 0.1 MPa, 35°C.
The compression ratio is 8. Heat supplied is 2100 kJ/kg. Calculate the maximum
pressure and temperature of the cycle, the cycle efficiency, and the mean
effective pressure. (For air, Cp = 1.005 kJ/kg K, Cv =
0.718 kJ/kg K and R = 0.287 kJ/kg K).
10.
Derive
the expression for air standard efficiency and mean effective pressure of a constant
pressure cycle.
or
11.
In
an air standard diesel cycle, the compression ratio is 16, and at the beginning
of isentropic compression, the temperature is 150C and the pressure
is 0.1 MPa. Heat is added until the temperature at the end of the constant
pressure process is 14800 C. Calculate the cut–off ratio, heat
supplied per kg of air, cycle efficiency and the m.e.p.
12.
Derive
the expression for air standard efficiency and mean effective pressure of a mixed
cycle.
or
13.
An
air standard dual cycle has a compression ratio of 16, and compression begins
at 1 bar, 50°C. The maximum pressure is 70 bar. The heat transferred to air at
constant pressure is equal to that at constant volume. Estimate the pressures
and temperatures at cardinal points of the cycle, the cycle efficiency and the
m.e.p. of the cycle. (For air, Cp = 1.005
kJ/kg K, Cv = 0.718 kJ/kg K and R = 0.287 kJ/kg K).
No comments:
Post a Comment